Answer
$f^{(n)}(x)=n!$
Work Step by Step
$f'(x)=nx^{n-1}$
$f''(x)=n(n-1)x^{n-2}$
$f'''(x)=n(n-1)(n-2)x^{n-3}$
...
$f^{(n)}(x)=n(n-1)(n-2)...(1)x^{n-n}=n!x^0=n!$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.3 Exercises - Page 128: 119
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