Answer
$v(3)=27$ meters per second
$a(3)=-6$ $m/s^2$
When velocity is positive and acceleration is negative, the object is moving forward, but it is slowing down.
Work Step by Step
Velocity
$v(t)=36-t^2$
$v(3)=36-(3)^2$
$v(3)=36-9$
$v(3)=27$ meters per second
Acceleration
$\frac{d}{dt}(v(t))=a(t)$
$\frac{d}{dt}(v(t))=\frac{d}{dt}(36-t^2)$
$a(t)=-2t$
$a(3)=-2(3)$
$a(3)=-6$ $m/s^2$
When velocity is positive and acceleration is negative, the object is moving forward, but it is slowing down.
