Answer
True.
Work Step by Step
Using the product rule:
$h'(x)=(f'(x))(g(x))+(g'(x))(f(x)).$
$h'(c)=(f'(c))(g(c))+(g'(c))(f(c))=0+0=0.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.3 Exercises - Page 128: 131
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