Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.1 Exercises - Page 105: 79

Answer

$(1,\infty)$

Work Step by Step

$\lim\limits_{x \to 1^-} \sqrt {x-1}$ does not exist because the domain of $\sqrt {x-1}$ is $[1, \infty)$. Hence it is not differentiable at $x=1$ or less.
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