Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.1 Exercises: 76

Answer

$(-\infty, -3) \cup (-3, 3) \cup (3,\infty)$

Work Step by Step

Sharp turn at $x=-3$ and $x=3$. This means that $\lim\limits_{x \to -3^-} f(x) ≠ \lim\limits_{x \to -3^+} f(x)$ and $\lim\limits_{x \to 3^-} f(x) ≠ \lim\limits_{x \to 3^+} f(x)$. Hence it is not differentiable at $x=-3$ and $x=3$
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