Answer
Not differentiable at x=1.
Work Step by Step
$\lim\limits_{x \to 1^-}(|x-1|)=0$
$\lim\limits_{x \to 1^+}(|x-1|)=0$
Even though the function is continuous at x=1, the function is not differentiable because there is a sharp point at x=1.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.1 Exercises - Page 105: 85
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