Answer
The solutions are
a) $f(0,5,4) = 3.$
b) $f(6,8,-3) =\sqrt{11}.$
c) $f(4,6,2)= 2\sqrt{3}.$
d) $f(10,-4,-3) =\sqrt{3}.$
Work Step by Step
We will substitute $x$, $y$ and $z$ from the first, the second and the third coordinate from the given point into the function $f(x,y,z) = \sqrt{x+y+z}$.
a) $f(0,5,4) = \sqrt{0+5+4} = \sqrt{9} = 3.$
b) $f(6,8,-3)=\sqrt{6+8-3} =\sqrt{11}.$
c) $f(4,6,2)=\sqrt{4+6+2}=\sqrt{12} = 2\sqrt{3}.$
d) $f(10,-4,-3)=\sqrt{10-4-3} = \sqrt{3}.$
