Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.5 Exercises - Page 88: 5

Answer

$\lim\limits_{x\to4^-}f(x)=-\infty.$ $\lim\limits_{x\to4^+}f(x)=+\infty.$

Work Step by Step

$\lim\limits_{x\to4^-}f(x)=\lim\limits_{x\to4^-}\dfrac{1}{x-4}=\dfrac{1}{4^--4}=\dfrac{1}{0^-}=-\infty.$ $\lim\limits_{x\to4^+}f(x)=\lim\limits_{x\to4^+}\dfrac{1}{x-4}=\dfrac{1}{4^+-4}=\dfrac{1}{0^+}=+\infty.$
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