Answer
Vertical asymptote at $s=4$ and at $s=-4.$
Work Step by Step
$h(s)=\dfrac{3s+4}{s^2-16}=\dfrac{3s+4}{(s-4)(s+4)}$
Vertical asymptotes occur when the denominator alone is $0\to$
$(s-4)(s+4)=0\to s=4$ or $s=-4.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.5 Exercises - Page 88: 18
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