Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.5 Exercises - Page 88: 23

Answer

No vertical asymptotes.

Work Step by Step

$f(x)=\dfrac{x^2-2x-15}{x^3-5x^2+x-5}=\dfrac{(x-5)(x+3)}{(x-5)(x^2+1)}=\dfrac{x+3}{x^2+1}.$ Vertical asymptotes occur when the denominator alone is $0\to$ $x^2+1=0\to x^2=-1$ which has no real solution, hence the function has no vertical asymptotes.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.