## Calculus 10th Edition

$\lim\limits_{x \to 0} f(x)$ = 4.
$\lim\limits_{x \to 0} 4-x^{2}$ $\leq$ $\lim\limits_{x \to 0} f(x)$ $\leq$$\lim\limits_{x \to 0} 4+x^{2} 4\leq \lim\limits_{x \to 0} f(x)$$\leq$4 Therefore, $\lim\limits_{x \to 0} f(x)$ = 4.