Answer
$\lim\limits_{h\to0}\dfrac{(1-\cos{h})^2}{h}=0.$
Work Step by Step
$\lim\limits_{h\to0}\dfrac{(1-\cos{h})^2}{h}=\lim\limits_{h\to0}\dfrac{1-\cos{h}}{h}\times\lim\limits_{h\to0}(1-\cos{h})=1(1-\cos{0})$
$=(0)(0)=0.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 68: 69
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