Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 68: 84

Answer

$\lim\limits_{\Delta x\to0}\dfrac{-6(x+\Delta x)+3-(-6x+3)}{\Delta x}=-6.$

Work Step by Step

$\lim\limits_{\Delta x\to0}\dfrac{-6(x+\Delta x)+3-(-6x+3)}{\Delta x}$ $=\lim\limits_{\Delta x\to0}\dfrac{-6x-6\Delta x+3+6x-3}{\Delta x}$ $=\lim\limits_{\Delta x\to0}\dfrac{-6\Delta x}{\Delta x}=-6.$
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