Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 9 - Infinite Series - 9.5 The Comparison, Ratio, And Root Tests - Exercises Set 9.5 - Page 636: 9



Work Step by Step

Factoring out the constant $ \frac{1}{\sqrt[3] {8k^2-3k}}$ leaves $$\Sigma^m_{k=1} \frac{1}{\sqrt[3] {8k^2-3k}}$$ This is a p-series with p<1, so the series Diverges.
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