Answer
$y = - 2x^2 + 2x + 3$
Work Step by Step
$y' = 2 - 4x$ to find $y$, integrate $y'$
$ y = \int (2 - 4x) dx$
$y = - 2x^2 + 2x + C$
Find C when $y(0) = 3 $
$3 = - 2(0)^2 + 2(0) + C$
$ C = 3 $
Rewrite the equation with the value of C
$y = - 2x^2 + 2x + 3$