Answer
$c_1 = 1$
$c_2 = -3 $
$y = e^{4x} -3 xe^{4x}$
Work Step by Step
$y = c_1e^{4x} +c_2xe^{4x} $
$y' = 4c_1e^{4x} +c_2(4x+1)e^{4x} $
Plug in the value $y(0) = 1$
$y(0) = c_1e^{4(0)} +c_2(0)e^{4(0)} = 1$
$c_1 = 1 ............... (1)$
Plug in the value $y'(0) = 1$
$y'(0) = 4c_1e^{4(0)} +c_2(4(0)+1)e^{4(0)} = 1$
and $c_1 = 1$
$4(1) + c_2 = 1..............(2)$
we get
$c_1 = 1$
$c_2 = -3 $
Rewrite the original equation with values of $c_1$ and $c_2$
$y = e^{4x} -3 xe^{4x}$