Answer
$\frac{1}{4}e^{x^4}+C$
Work Step by Step
Let $u=x^4$. Then $du=4x^3dx$, so $x^3dx=\frac{1}{4}du$.
$\int x^3e^{x^4}dx$
$=\int e^u*\frac{1}{4}du$
$=\frac{1}{4}e^u+C$
$=\frac{1}{4}e^{x^4}+C$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 6 - Exponential, Logarithmic, And Inverse Trigonometric Functions - 6.3 Derivatives Of Inverse Functions; Derivatives And Integrals Involving Exponential Functions - Exercises Set 6.3 - Page 433: 68
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