## Calculus, 10th Edition (Anton)

$e^{\sin(x)}+C$
Using a u-substitution of $u=sin(x)$ yields $du=cos(x)dx$ and makes the integral $$\int{e^{u}}du=e^{u}+C$$ Replacing $u$ in terms of $x$ yields $\boxed{e^{\sin(x)}+C}$.