Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.9 Evaluating Definite Integrals By Substitution - Exercises Set 4.9 - Page 341: 47

Answer

$$\frac{2}{\pi}$$

Work Step by Step

(a) We find: $\int_{0}^{1} \sin x \pi d x=\frac{1}{\pi} \int_{0}^{\pi} \cos u d u=2 \cdot \frac{1}{\pi} =\frac{2}{\pi}$ (b) We know: $\int_{0}^{1} \sin (x \pi) d x=\frac{2}{\pi} \approx 0.63662$
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