Answer
$$
4410.8
$$
Work Step by Step
Time to fill equals $\frac{\text {volume}}{\text {rate}}( h=5 f t,r=3 f t, $ fillrate=$\left.1 \frac{f t^{3}}{\min }\right)$
\[
45 \pi=\frac{ 3^{2}(5)* \pi }{1}
\]
Weight density of water: $62.4 \frac{l b}{f t^{3}}$; fill rate: $1 \frac{f t^{3}}{\min }$
\[
62.4 t=62.4 * t* 1
\]
Average weight of water in the tank over time required to fill it is:
\[
W_{a v e}=\frac{1}{45 \pi} \int_{0}^{45 \pi} 62.6 t d t=4410.8
\]
