Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.6 The Fundamental Theorem Of Calculus - Exercises Set 4.6 - Page 321: 53

Answer

See explanation.

Work Step by Step

(a) $F(4)=\int_{4}^{4} \sqrt{9+t^{2}} d t=0$ (b) \[ F^{\prime}(x)=\sqrt{9+x^{2}} \] And therefore: \[ F^{\prime}(4)=\sqrt{9+4^{2}}=\sqrt{25}=5 \] (c) \[ F^{\prime \prime}(x)=\frac{x}{\sqrt{9+x^{2}}} \] And therefore: \[ F^{\prime \prime}(4)=\frac{4}{\sqrt{9+4^{2}}}=\frac{4}{5} \]
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