Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.6 The Fundamental Theorem Of Calculus - Exercises Set 4.6 - Page 321: 48

Answer

See explanation.

Work Step by Step

(a) $F^{\prime}(x)=\cos 2 x$ (b) $F(x)=\int_{\pi / 4}^{x} \cos 2 t d t=\left(\frac{1}{2} \sin 2 t\right)_{\pi / 4}^{x}=-\frac{1}{2}+\frac{1}{2} \sin 2 x$ Differentiating then gives $F^{\prime}(x)=\cos 2 x$
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