Answer
$\text{Area} = 9 \,\text{Units square}$
Work Step by Step
Using the rules of integrals, we find:
$$\text { Area }=\int_{0}^{3} x^{2} d x=\left[\frac{x^{3}}{3}\right]_{0}^{3}=\frac{3^{3}}{3}=3^{2}=9 \,\text{Units square}$$
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