Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.1 An Overview Of The Area Problem - Exercises Set 4.1 - Page 270: 1

Answer

For n = 2, A = 0.854 Units square For n = 5, A = 0.750 Units square For n = 10, A = 0.711 Units square

Work Step by Step

1. First, consider n = 2 rectangles. This means we divide the given interval [0, 1] by 2. Thus, each subinterval has a length of $\frac{1}{n}$ = $\frac{1}{2}$. The endpoints of the subintervals: 1) f($\frac{1}{2}$) = $\frac{1}{\sqrt 2}$ = 0.707 2) f(1) = $\sqrt 1$ = 1 Finally, the total area of n = 2 rectangles: A = $A_{1}$ + $A_{2}$ = $\frac{1}{2}$ $\times$ (0.707 + 1) = 0.854 Units square 2. In the same way, we can consider n = 5 rectangles. This means we divide the given interval [0, 1] by 5. Thus, each subinterval has a length of $\frac{1}{n}$ = $\frac{1}{5}$. The endpoints of the subintervals: 1) f($\frac{1}{5}$) = $\frac{1}{\sqrt 5}$ = 0.447 2) f($\frac{2}{5}$) = $\sqrt {\frac{2}{5}}$ = 0.632 3) f($\frac{3}{5}$) = $\sqrt {\frac{3}{5}}$ = 0.775 4) f($\frac{4}{5}$) = $\sqrt {\frac{4}{5}}$ = 0.894 5) f(1) = $\sqrt 1$ = 1 Finally, the total area of n = 5 rectangles: A = $A_{1}$ + $A_{2}$ + $A_{3}$ + $A_{4}$ + $A_{5}$ = $\frac{1}{5}$ $\times$ (0.447 + 0.632 + 0.775 + 0.894 + 1) = 0.750 Units square 3. In the same way, we can consider n = 10 rectangles. This means we divide the given interval [0, 1] by 10. Thus, each subinterval has a length of $\frac{1}{n}$ = $\frac{1}{10}$. The endpoints of the subintervals: 1) f($\frac{1}{10}$) = $\frac{1}{\sqrt 10}$ = 0.316 2) f($\frac{2}{10}$) = $\sqrt {\frac{1}{5}}$ = 0.447 3) f($\frac{3}{10}$) = $\sqrt {\frac{3}{10}}$ = 0.548 4) f($\frac{4}{10}$) = $\sqrt {\frac{2}{5}}$ = 0.632 5) f($\frac{5}{10}$) = $\sqrt {\frac{1}{2}}$ = 0.707 6) f($\frac{6}{10}$) = $\sqrt {\frac{3}{5}}$ = 0.775 7) f($\frac{7}{10}$) = $\sqrt {\frac{7}{10}}$ = 0.837 8) f($\frac{8}{10}$) = $\sqrt {\frac{4}{5}}$ = 0.894 9) f($\frac{9}{10}$) = $\sqrt {\frac{9}{10}}$ = 0.949 10) f(1) = $\sqrt 1$ = 1 Finally, the total area of n = 10 rectangles: A = $A_{1}$ + $A_{2}$ + $A_{3}$ + $A_{4}$ + $A_{5}$ + $A_{6}$ + $A_{7}$ + $A_{8}$ + $A_{9}$ + $A_{10}$= $\frac{1}{10}$ $\times$ (0.316 + 0.447 + 0.548 + 0.632 + 0.707 + 0.775 + 0.837 + 0.894 + 0.949 + 1) = 0.711 Units square
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