Answer
No relative extrema.
Work Step by Step
First derivative
\[
-\frac{5}{(-2+x)^{2}}=f^{\prime}(x)
\]
Critical points (zeros of first derivative or point where the first derivative does not exist)
\[
2=x
\]
First derivative test
$f^{\prime}(x)<0$ on the left and $f^{\prime}(x)<0$ on the right of $x=2,$ so $x=2$ is not a relative extrema.
