Answer
\[\begin{align}
& \left( \mathbf{a} \right)\text{increasing on the interval }\left( -\infty ,\infty \right) \\
& \left( \mathbf{b} \right)\text{none} \\
& \left( \mathbf{c} \right)\text{concave upward on the interval }\left( -\frac{1}{2},+\infty \right) \\
& \left( \mathbf{d} \right)\text{concave downward on the interval }\left( -\infty ,-\frac{1}{2} \right) \\
& \left( \mathbf{e} \right)\text{inflection point at }x=-\frac{1}{2} \\
\end{align}\]
Work Step by Step
\[\begin{align}
& f\left( x \right)={{\left( 2x+1 \right)}^{3}} \\
& \text{The domain of the function is }\left( -\infty ,\infty \right) \\
& \text{Calculate the first and second derivatives} \\
& f'\left( x \right)=\frac{d}{dx}\left[ {{\left( 2x+1 \right)}^{3}} \right] \\
& f'\left( x \right)=3{{\left( 2x+1 \right)}^{2}}\left( 2 \right) \\
& f'\left( x \right)=6{{\left( 2x+1 \right)}^{2}} \\
& \text{Find the critical points, set }f'\left( x \right)=0 \\
& f'\left( x \right)=6{{\left( 2x+1 \right)}^{2}} \\
& x=-\frac{1}{2},\text{ interval analysis }\left( -\infty ,-\frac{1}{2} \right),\text{ }\left( -\frac{1}{2},\infty \right) \\
& f''\left( x \right)=\frac{d}{dx}\left[ 6{{\left( 2x+1 \right)}^{2}} \right] \\
& f''\left( x \right)=12\left( 2x+1 \right)\left( 2 \right) \\
& f''\left( x \right)=24\left( 2x+1 \right) \\
& f''\left( x \right)=0 \\
& x=-\frac{1}{2} \\
& \text{We obtain the sign analysis shown in the following tables} \\
& \begin{matrix}
\text{Interval} & \left( -\infty ,-\frac{1}{2} \right) & \left( -\frac{1}{2},\infty \right) \\
\text{Test Value} & x=-1 & x=0 \\
\text{Sign of }f'\left( x \right) & + & + \\
\text{Conclusion} & \text{Increasing} & \text{Increasing} \\
\end{matrix} \\
& \\
& \begin{matrix}
\text{Interval} & \left( -\infty ,-\frac{1}{2} \right) & \left( -\frac{1}{2},+\infty \right) \\
\text{Test Value} & x=-1 & x=0 \\
\text{Sign of }f''\left( x \right) & - & + \\
\text{Conclusion} & \text{Concave downward} & \text{Concave upward} \\
\end{matrix} \\
& \\
& \text{Summary:} \\
& \left( \mathbf{a} \right)\text{ }f\left( x \right)\text{ is increasing on the interval }\left( -\infty ,\infty \right) \\
& \left( \mathbf{b} \right)\text{None} \\
& \left( \mathbf{c} \right)\text{ }f\left( x \right)\text{ is concave upward on the interval }\left( -\frac{1}{2},+\infty \right) \\
& \left( \mathbf{d} \right)\text{ }f\left( x \right)\text{ is concave downward on the interval }\left( -\infty ,-\frac{1}{2} \right) \\
&\left( \mathbf{e} \right)\text{ Inflection point at }x=-\frac{1}{2} \\
\end{align}\]