Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - Chapter 2 Review Exercises - Page 184: 20

Answer

a) 28 b) 75

Work Step by Step

a) The average rate of change is equal to $\frac{V(4)-V(2)}{4-2} = \frac{4^3-2^3}{4-2} = \frac{64-8}{2} = \frac{56}{2} = 28$ b) To find the instantaneous rate, we take the derivative of $V$: $V'(l) = 3l^2$ $V'(5) = 3(5)^2=75$
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