Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 14 - Multiple Integrals - 14.1 Double Integrals - Exercises Set 14.1 - Page 1007: 26

Answer

True

Work Step by Step

The statement is true as shown below: $0=\iint_{R} f(x, y) d A$ $0=\iint_{R_{1}+R_{2}} f(x, y) d A$ $0=\iint_{R_{1}} f(x, y) d A+\iint_{R_{2}} f(x, y) d A$ $-\iint_{R_{2}} f(x, y) d A=\iint_{R_{1}} f(x, y) d A$
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