Answer
$$\int_0^1\int_0^2(x+3)dydx=7$$
Work Step by Step
$\int_0^1\int_0^2(x+3)dydx=\int_0^1(xy+3y)\bigg\vert_0^2dx$
$=\int_0^1(2x+6-0)dx=\left(x^2+6x\right)\bigg\vert_0^1$
$=1+6-0-0=7$
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