Answer
$$\int_1^3\int_{-1}^1(2x-4y)dydx=\boxed{16}$$
Work Step by Step
$\int_1^3\int_{-1}^1(2x-4y)dydx=\int_1^3\left(2xy-2y^2\right)\big\vert_{-1}^1dx=\int_1^3(2x-2-(-2x-2))dx=\int_1^34xdx=2x^2\bigg\vert_1^3=18-2=16$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 14 - Multiple Integrals - 14.1 Double Integrals - Exercises Set 14.1 - Page 1007: 2
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