Answer
(a) $\quad C(25,3)=5\left(e^{-0.6}-e^{-3}\right)=2.50 \mathrm{mg} / \mathrm{L}$
(b) $C(100, t)=20\left(e^{-0.2 t}-e^{-t}\right)$
(c) $C(x, 1)=0.2 x\left(e^{-0.2}-e^{-1}\right)$
Work Step by Step
Plugging in the given points:
(a) $\quad C(25,3)=5\left(e^{-0.6}-e^{-3}\right)=2.50 \mathrm{mg} / \mathrm{L}$
(b) $C(100, t)=20\left(e^{-0.2 t}-e^{-t}\right)$
(c) $C(x, 1)=0.2 x\left(e^{-0.2}-e^{-1}\right)$