Answer
The answer is below.
Work Step by Step
$(a)$
$\mathrm{At}\ T=35, \quad 14=5+9=5+\sqrt{\frac{9}{10}}(15-5)$
$W C I \approx 31+\left[\frac{9}{10}\right](25-31)=25.6^{\circ} F$
(b) At $v=15, \quad 32=30+\sqrt{\frac{2}{5}}(35-30),$ so
$W C I \approx 19+\left[\frac{2}{5}\right](25-19)=21.4^{\circ} F$