Answer
relative humidity $\approx 77+(1 / 5)(79-77)=77.6 \%$
Work Step by Step
Plugging in the given values into the equation:
\begin{array}{l}
\text { (a) } \\
\qquad 4^{\circ} \mathrm{C} \\
\text { (b) } \\
\text { relative humidity } \approx 62-(1 / 4) 9=59.75 \% \\
\text { (c) }
\end{array}
relative humidity $\approx 77+(1 / 5)(79-77)=77.6 \%$