Answer
$$28$$
Work Step by Step
Given $$\lim_{x\to 0} \frac{\tan3x^2+\sin^25x}{x^2} $$
Then \begin{align*}
\lim_{x\to 0} \frac{\tan3x^2+\sin^25x}{x^2}&=\lim_{x\to 0} \frac{\tan3x^2 }{x^2}+\lim_{x\to 0} \frac{ \sin^25x}{x^2}\\
&=\lim_{3x^2\to 0} \frac{3\tan3x^2 }{3x^2}+25\left(\lim_{x\to 0} \frac{ \sin 5x}{5x }\right)^2\\
&=3(1)+25(1)\\
&=28
\end{align*}