Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 5 - Section 5.4 - Indefinite Integrals and the Net Change Theorem - 5.4 Exercises - Page 416: 58

Answer

$\frac{1}{5}$

Work Step by Step

Since $y = \sqrt[4] x$, then $x = y^4$ We can evaluate the integral to find the area of the region: $\int_{0}^{1}y^4~dy$ $=\frac{y^5}{5}~\vert_{0}^{1}$ $=(\frac{1^5}{5})-(\frac{0^5}{5})$ $=\frac{1}{5}$
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