Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 5 - Review - True-False Quiz - Page 428: 7

Answer

True

Work Step by Step

True. Let $f'(v)=g(v)$ and $f(v)=G(v)$ Since $f'$ is continuous on $[1,3]$, so is $g$. It follows by the Fundamental Theorem of Calculus in Part 2 that $\int_1^3f'(v)dv=\int_1^3g(v)=G(3)-G(1)=f(3)-f(1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.