Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 5 - Review - True-False Quiz - Page 428: 6

Answer

True

Work Step by Step

True. Let $z=x$. Then, a) The new lower bound: $z_1=x_1=a$ b) The new upper bound: $z_2=x_2=b$ c) $\frac{dz}{dx}=1\to dz=dx$ Using the substitution rule, we get $\int_a^bf(x)dx=\int_{a}^{b}f(z)dz$
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