Answer
$3$
Work Step by Step
$\int_1^2h''(u)du=\int_1^2(h')'(u)du$ (Use the Fundamental Theorem of Calculus in Part 2)
$=h'(2)-h'(1)$ (Substitute $h'(2)=5$ and $h'(1)=2$)
$=5-2$
$=3$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 5 - Review - Exercises - Page 431: 74
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