Answer
$y′=x(2sin(πx)+πxcos(πx))$
Work Step by Step
Start with the function: $y=x^2sin(πx)$.
Use the product rule to differentiate: $y′=2xsin(πx)+πx^2cos(πx)$.
Factor out the common $x$ term to arrive at the answer: $y′=x(2sin(πx)+πxcos(πx))$.
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 3 - Review - Exercises - Page 270: 5
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