Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 11 - Section 11.4 - The Comparison Tests - 11.4 Exercises - Page 765: 39

Answer

Diverges

Work Step by Step

We know that $\tan\frac{1}{n}\leq \tan 1\approx 1.56$ for all $n\geq 1$ since for $0\leq x\leq 1$ the function $\tan x$ is increasing. Then, $\frac{1}{n}\tan\frac{1}{n}\geq \frac{1}{n}$ for all $n$ Since the series $\sum_{n=1}^\infty\frac{1}{n}$ diverges, it follows by the Direct Comparison Test with $a_n=\frac{1}{n}\tan\frac{1}{n}$ and $b_n=\frac{1}{n}$ that the series $\sum_{n=1}^\infty\frac{1}{n}\tan\frac{1}{n}$ diverges.
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