Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 10 - Section 10.6 - Conic Sections in Polar - 10.6 Exercises - Page 717: 9

Answer

Graph IV

Work Step by Step

Find $e$ and $d$: $r=\frac{3}{1-\sin\theta}$ $\frac{ed}{1-e\sin\theta}=\frac{3}{1-1\sin\theta}$ $e=1$ and $ed=3$ $e=1$ and $d=3$ Using Theorem 6, and using part (c) of Figure 2, the given polar equation represents a vertical parabola with the directrix $y=-3$. It is shown in Graph VI.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.