Answer
Graph IV
Work Step by Step
Find $e$ and $d$:
$r=\frac{3}{1-\sin\theta}$
$\frac{ed}{1-e\sin\theta}=\frac{3}{1-1\sin\theta}$
$e=1$ and $ed=3$
$e=1$ and $d=3$
Using Theorem 6, and using part (c) of Figure 2, the given polar equation represents a vertical parabola with the directrix $y=-3$.
It is shown in Graph VI.