Answer
Graph I
Work Step by Step
Find $e$ and $d$:
$r=\frac{3}{2-2\cos\theta}$
$\frac{ed}{1-e\cos\theta}=\frac{\frac{3}{2}}{1-1\cos\theta}$
$e=1$ and $d=\frac{3}{2}$
Using Theorem 6, and using part (b) of Figure 2, the given polar equation represents a horizontal parabola with the directrix $x=-\frac{3}{2}$.
It is shown in Graph I.
