Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 708: 2

Answer

Vertex: $(0,0)$ Focus: $\left(\frac{9}{4},0\right)$ Directrix: $x=-\frac{9}{4}$

Work Step by Step

Recall: The parabola $4px=y^2$ has a vertex at $(0,0)$, a focus at $(p,0)$, and a directrix $x=-p$. We have $9x=y^2$. Then, $4p=9$ $p=\frac{9}{4}$ So, the vertex is $(0,0)$, the focus is $(\frac{9}{4},0)$, and the directrix $x=-\frac{9}{4}$. Sketch the graph:
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