Answer
No
Work Step by Step
$x^2+(y-3)^2=5$
In this equation, $y$ is not a function of $x$ because for some input values, there are two possible output values. For example, consider $x=1$.
$1^2+(y-3)^2=5$
$(y-3)^2=4$
$y-3=\pm2$, which means $y-3=2$ or $y-3=-2$.
Therefore, $y$ can be either $5$ or $1$.
See image for graph of function. Notice it does not pass the vertical line test.
