Answer
Yes
Work Step by Step
Let us solve for $y$.
$-2y=5-3x^2$
$y=\frac{5-3x^2}{-2}$
$y$ is uniquely defined for all $x$, so the given equation defines $y$ as a function of $x$. So the equation defines a function.
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 18: 8
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