Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Test - Page 264: 20

Answer

$$142.857 \ \Omega.$$

Work Step by Step

We have $$\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}=\frac{1}{225}+\frac{1}{475}+\frac{1}{ 925}\\ =0.004+0.002+0.001=0.007 $$ Hence, we get $$R=\frac{1}{0.007}=142.857 \ \Omega.$$
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