Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Test - Page 264: 17


$$\approx 19$$

Work Step by Step

We find $R$ by dividing both sides by $I^2$ as follows: $$P=I ^2R\Longrightarrow \frac{P}{I^2}\Longrightarrow R=\frac{P}{I^2} .$$ Now, by substituting, we get $$ R=\frac{480}{5^2}=\frac{96}{5}=19\frac{1}{5} \approx 19$$
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