Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Test - Page 264: 18


$$25 .$$

Work Step by Step

We find $b$ by multiplying both sides by 2 as follows: $$ A=\frac{1}{2}h(a+b)\Longrightarrow 2A=ha+hb \\\Longrightarrow hb=2A-ha.$$ By dividing both sides by $h$, we get $$ b=\frac{2A-ha}{h}=\frac{2A}{h}-a. $$ By substituting, we have $$ b=\frac{2*260}{13}-15=40-15=25 .$$
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