## Elementary Technical Mathematics

$175^oC=347^oF.$
Since we have $$C=\frac{5}{9}(F -32)$$ then by multiplying both sides by $\frac{9}{5}$, we get the formula $\frac{9}{5}C=F-32$ and hence we get $$F=\frac{9}{5} C +32^o=\frac{9}{5} ( 175^o)+32^o\\ =315^o+32^o=347^o$$ That is, $175^oC=347^oF.$