Answer
$$v_0= 2 v-v_f .$$
Work Step by Step
We have:
$$v=\frac{v_f+v_0}{2}$$
We multiply both sides by $2$ and then group the like terms:
$$2v=\frac{v_f+v_0}{2}2\Longrightarrow2 v=v_f+v_0\Longrightarrow v_0= 2 v-v_f .$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 6 - Review - Page 263: 29
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